Another rock in Death Valley at the Racetrack traveled 55.3 meters during the observation period of nine years. a . What was the rock's average speed in feet per year? Round your answer to the nearest whole number. feet per year b . If a strong wind gives a stone an initial velocity of v 0 = 11 m / s , and the friction coefficient of stone on ice is μ = 0.14 , and g = 9.81 m / s 2 . Use the equation v 2 0 = 2 μ g S to find the stopping distance S for the stone. Round your answer to the nearest tenth.

Answer:a) 20 feet per yearb) 44.1 m Step-by-step explanation:Given:Distance traveled during the observation period = 55.3 metersObservation period = 9 yearsinitial velocity of v₀ = 11 m/sfriction coefficient of stone on ice is μ = 0.14 g = 9.81 m/s²also,v₀² = 2μgSNow, 1 m = 3.28084 ftthus,Total distance in feet = 55.3 × 3.28084 = 181.430452 ftAverage speed = [tex]\frac{\textup{Distance}}{\textup{Time}}[/tex] orAverage speed = [tex]\frac{\textup{181.430452}}{\textup{9}}[/tex] orAverage speed = 20.159 feet/year ≈ 20 feet per yearb) v₀² = 2μgSsubstituting the values in the above equation, we get11² = 2 × 0.14 × 9.81 × sor121 = 2.7468 × sors = 44.051 ≈ 44.1 m